Matlab Curve Fitting Tutorial
Curve fitting is the process of matching the pattern data in the form of a graph into an equation . The simple notion that changing the graphics data into an equation that can represent the graph. this can be done easily in matlab . follow the following tutorial:
1. Open matlab
2. prepare your chart data . if it does not have as an example here we create a data chart with the following equation .
type in the command windows matlab
x = -10 : 0.1 : 10 ;
y = x ^ .2 + 10 ;
make sure the workspace window there is a data x and y .
3. type cftool to use matlab curve fitting , then you will see a dialog like the following illustration:
4. then select the x data with ' x ' and y data with ' y ' which we have generated by typing the equation above earlier . then the graph will automatically display the data in graphical form as shown below .
5. from the picture above we can see there are two lines , the color black is the data that we have , and the blue is estimated data with polynomial formula . of the graph we can see there is no match at all . then we find the formula or degree option available on the column polynomial
6. Let's first try to increase the degree of the polynomial into two . As a result as follows :
from the picture above shows the blue line resembles the outline of a black color , so that it can be said of this equation is appropriate to represent the equation y = x ^ .2 + 10 . The new equation we get we can see on the left side of the graph . as follows:
can be seen from the picture above the new equation that represents the graph , ie
y = p1 * x ^ 2 + x + p2 * p3
with the value of p1 , p2 , p3 as written above , by ignoring the very small value ie p2 . then we will get a new equation above becomes
y = x ^ 2 + 10 .. so the curve fitting equation is able to recognize up to 99 % .
y = p1 * x ^ 2 + x + p2 * p3
with the value of p1 , p2 , p3 as written above , by ignoring the very small value ie p2 . then we will get a new equation above becomes
y = x ^ 2 + 10 .. so the curve fitting equation is able to recognize up to 99 % .
to represent the data above , we do not have to use a polynomial equation , you can also try the exponential or Gaussian degree 2 equation , but the result is less good for the exponential gaussian results are compared with the second degree .
for exponential equations that represent the data is :
for exponential equations that represent the data is :
f(x) = a*exp(b*x) + c*exp(d*x)
Coefficients (with 95% confidence bounds):
a = 7.948 (7.274, 8.622)
b = -0.2705 (-0.2804, -0.2606)
c = 7.948 (7.275, 8.622)
d = 0.2705 (0.2606, 0.2804)
a = 7.948 (7.274, 8.622)
b = -0.2705 (-0.2804, -0.2606)
c = 7.948 (7.275, 8.622)
d = 0.2705 (0.2606, 0.2804)
and for gaussian is :
f(x) = a1*exp(-((x-b1)/c1)^2) + a2*exp(-((x-b2)/c2)^2)
Coefficients (with 95% confidence bounds):
a1 = 173.8 (168.3, 179.4)
b1 = 15.77 (15.5, 16.05)
c1 = 8.442 (8.306, 8.579)
a2 = 173.8 (168.3, 179.4)
b2 = -15.77 (-16.05, -15.5)
c2 = 8.442 (8.306, 8.579)
Good luck with your data .
Hopefully this article helps you , :)





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